You are watching: What is the square root of negative 16
If you write `sqrt(16)` this is equal to 4. This is since the `sqrt(n)` without a authorize in prior signifies the principal square source which is constantly positive. To represent both the hopeful and an adverse square root we usage `+-sqrt(16)` i m sorry is same to both +4 and also -4. But when...
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If you write `sqrt(16)` this is equal to 4. This is since the `sqrt(n)` there is no a sign in former signifies the principal square source which is always positive. To signify both the hopeful and an unfavorable square root we use `+-sqrt(16)` i m sorry is equal to both +4 and also -4. However when friend ask in native what is the square root of 16 it is 4 or -4. The factor for this is that `y=sqrt(x)` is a function, when `y=+-sqrt(x)` is no a duty because one value of x offers two outputs.
Hope that helps...
Actually, it is!
The kind for a square root (otherwise recognized as a radical) is
r^2 = x
which method that the square source of x is a number r, which when multiplied by chin (r * r) yields x.
So in this case, 4^2 = (4 * 4) = 16, yet also
(-4)^2 = (-4 * -4) = 16
So any kind of positive actual number, like 16, actually has 2 square roots, one positive, the various other negative. The positive square root is termed the "principal square root," the an unfavorable square source is unfortunately unnamed. For this reason there"s a bit of a misnomer; once you speak "square root" it really refers to both an adverse and positive roots, however it has pertained to mean only the hopeful square root.
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