how to acquire the simplest form of this radical expression: \$\$3sqrt<3>2a - 6sqrt<3>2a\$\$

Here is my work:\$\$3sqrt<3>2a - 6sqrt<3>2a\$\$Since the radicands are the same, we just include the coefficients. \$\$-3sqrt<3>2a sqrt<3>2a\$\$Since every little thing is under the very same index the becomes:\$\$-3sqrt<3>2 sqrt<3>a\$\$

Did I perform this correctly, if not deserve to anyone phone call me what I must do?Thanks :-).

You are watching: What is the simplest form of the expression sqrt 3-sqrt 6/sqrt 3+sqrt 6

We have the right to factor, together an alternative, to acquire the very same result:

\$\$3sqrt<3>2a - 6sqrt<3>2a = 3sqrt<3>2a(1 - 2) = -3sqrt<3>2a\$\$

(I don"t see any type of need come write: \$;-3sqrt<3>2a = -3sqrt<3>2 sqrt<3>a)\$

Note that \$-3sqrt<3>2asqrt<3>2a = -3sqrt<3>4a^2 eq -3sqrt<3>2a \$

Your center step is incorrect, it have to be \$-3sqrt<3>2a\$ no \$-3sqrt<3>2asqrt<3>2a\$. It should be \$\$3sqrt<3>2a - 6sqrt<3>2a = 3 imessqrt<3>2a - 6 imessqrt<3>2a = (3 - 6) imessqrt<3>2a = -3 imessqrt<3>2a = -3sqrt<3>2a.\$\$ ns don"t think \$-3sqrt<3>2sqrt<3>a\$ is any kind of simpler 보다 \$-3sqrt<3>2a\$, but that"s just my opinion.

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