i am grounding on a trouble for mine stats class. I have not done any kind of work yet I will explain why. Here is the problem;

A coin is flipped until you gain a tails. What is the probability ofgetting at the very least 4 heads?

I have actually done probability with coins before, however this concern stumped me. How? due to the fact that we only have ONE coin, and we don"t recognize how plenty of times the coin is tossed. I recognize that with one coin, the probability of getting a head is 1. And the variety of outcomes is 2. However, ns don"t recognize the following step after this, specifically when I"m not offered information on how countless times the coin must be tossed.

You are watching: What is the probability of getting tails 4 times in a row when you flip a coin?

Any aid would be great. Or maybe simply a tip on looking in ~ this difficulty from a various perspective? say thanks to you!


I"ve also started statistics together well.

How ns look into this concern is the other way around:

Rather than in search of 4 in a row, i look at the probability of not having 4 top in a heat (having the compliment of the probability).

Let speak P(A) = having at least 4 heads before very first tail

$P(A") = P(T)+P(H\cap T)+P(H\cap H \cap T)+P(H \cap H \cap H \cap T)$

$P(A")+P(A) = 1 \rightarrow P(A) = 1-P(A") $

$1-P(T)+P(H\cap T)+P(H\cap H \cap T)+P(H \cap H \cap H \cap T)$


You desire the probability that flipping in ~ least four heads before obtaining the very first tail.

Thus you desire the probability the at least the an initial four tosses space heads.

This is $1/2^4$.


The probability of getting a heads an initial is 1/2.The probability of getting 2 heads in a heat is 1/2 the that, or 1/4.The probability of gaining 3 heads in a heat is 1/2 that that, or 1/8.The probability of obtaining 4 top in a heat is 1/2 of that, or 1/16.

After that... It doesn"t matter... You have actually at the very least 4 heads.

The price is 1/16.


There room several feasible approaches.

Getting 4 top to start has actually probability $(1/2)^4 = 1/16$ together inthe comment by

More formally, outcomes that satisfy your problem areHHHHT, HHHHHT, HHHHHHT, etc. So the total probabilityis the geometric series with probability $A = (1/2)^5 + (1/2)^6 + (1/2)^7 + \dots .$

There is a formula for summing this series. If you don"t know it, friend cannote that $(1/2)A = (1/2)^6 + 1/2)^7 + \dots,$ therefore that$A - (1/2)A = = (1/2)A = (1/2)^5$ and $A = (1/2)^4,$ i m sorry is the very same as the previous answer.

I perform not understand why
manmood (+1) that appeared while was inputting this.I hope one of these explanations is clear to you. The an essential points throughoutis that we"re presume the coin is fair <$P(H) = 1/2$> and that the tosses room independent.

Also, if your book includes the geometric distribution, you must lookat that due to the fact that it is related to this problem. I don"t desire to discussthe geometric circulation in this Answer due to the fact that there room at leasttwo execution of it, and discussing the wrong one might be confusing.


Well, h=heads, t=tailsSample space=(hhhh),(hhht),(hhth),(hhtt),(hthh),(htht),(htth),(httt), (thhh),(thht),(thth),(thtt),(tthh),(ttht),(ttth),(tttt)There are 16 total outcomes, and also only 1 of these outcomes outcomes in 4 heads. This means the probability of landing every 4 heads in 4 tosses is 1 the end of the 16.So the prize is 1/16.As for the "before flipping a tail", that doesn"t seem to matter because no issue the outcome there is still only 1 in 16 chances to get 4 top flipped.

The Probability of tossing 4 heads is a row is usually the multiplication of the probability of each toss that a head i m sorry is 1/2

P(H,H,H,H) = 1/2 * 1/2 * 1/2 * 1/2 = 1/16

Thanks because that contributing an answer to aramuseum.orgematics ridge Exchange!

Please be certain to answer the question. Administer details and also share your research!

But avoid

Asking for help, clarification, or responding to various other answers.Making statements based upon opinion; back them up with references or personal experience.

Use aramuseum.orgJax to layout equations. Aramuseum.orgJax reference.

See more: Which Of The Following Would Not Increase Gdp? ? Gross Domestic Product, Economic Lowdown Podcasts

To find out more, check out our tips on writing good answers.

article Your price Discard

By clicking “Post your Answer”, friend agree to our regards to service, privacy policy and also cookie policy

Not the answer you're spring for? Browse various other questions tagged probability statistics or asking your very own question.

Probability of selecting a biased coin $C$ which has actually probability $3/15$ of getting heads, assuming we acquired head on the an initial toss
site architecture / logo design © 2021 ridge Exchange Inc; user contributions license is granted under cc by-sa. Rev2021.9.24.40305

your privacy

By click “Accept every cookies”, you agree ridge Exchange have the right to store cookie on your device and disclose details in accordance with our Cookie Policy.