The amount of the oxidation states of all of the atoms requirements to same the full charge on the ion.
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For example, because that $\ceNH4+$, if every hydrogen atom has actually an oxidation state that +1, and also the as whole charge is +1, climate we deserve to solve because that the oxidation state the nitrogen:
$$\beginaligned 4(+1) + OS_\ceN &= +1\\OS_\ceN &= +1 -4(+1) \\OS_\ceN &= -3\endaligned$$
Similarly, we have the right to do $\ceSO4^2-$. If every oxygen atom has an oxidation state the -2, and also the all at once charge is -2, we deserve to solve because that the oxidation state that sulfur:
$$\beginaligned 4(-2) + OS_\ceS &= -2\\OS_\ceS &= -2 -4(-2) \\OS_\ceS &= +6\endaligned$$
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answered january 6 "19 in ~ 12:28
Ben NorrisBen Norris
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Seeing together Oxygen has actually an oxidation state of -2 and you have actually 4 Oxygen atoms, the full charge contributed by Oxygen = -8. Since the total charge the this link = -1, then in this case Mn = +7+7 - 8 = -1
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answered january 6 "19 in ~ 13:32
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As you said Oxygen has actually the oxidation state of -2 so if we include up all the oxygens they have actually a -8 oxidation state.
As the oxidation state of the ion is same to the charge, the Mn has to "balance" the -8 to gain it approximately -1. Therefore the oxidation state the Mn in Mno4- is +7.
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answered january 6 "19 in ~ 13:33
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