You are watching: The vertical _____ of the function secant are determined by the points that are not in the domain.
The vertical asymptote that a function secant are established by the point out that space not in the domain.
The domain of a function is the collection of x values for which the function is defined.
Secant function is not defined at
It method we cannot encompass these point out in the domain.
At these points, us must have actually a vertical line which execute not touch the graph. These lines are called "Vertical asymptotes"
Vertical asymptotes are not contained in the domain that the function.
Haramuseum.orgce, the exactly word have to be "Asymptote"
The vertical asymptote of a duty secant are figured out by the clues that are not in the domain.
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A rectangle has a laramuseum.orggth of x and also a width that is 8 units much shorter than double the laramuseum.orggth.
laramuseum.orggth = x
width = 2x-8
b.) to gain the area you have to multiply the laramuseum.orggth and also the width.
c.) 2x^2-8x = 10
subtract 10 both sides
2x^2-8x-10 = 0
2(x^2-4x-5) = 0
2(x-5)(x+1) = 0
x = 5
the area would certainly be 10.
7 month ago
PLEASE prize THIS ASAP !!!
No.In the relationship , y is no a function of x, because for the second input that x, over there is 2 outputs the y. Every x-value have the right to only have actually one matching y-value
8 months ago
Help me the end please!!
64899.4 is the answer
6 months ago
Which is no a great reason to carry out step 1 in the solution shown?
B.) divide by 8 since 8 is a aspect of 48.
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It"s true, it"s simply not a an excellent reason. Sometimes wharamuseum.org we divide both political parties of one equation by a number everything works the end evaramuseum.orgly, occasionally it doesn"t, yet either way it"s a step toward the answer, possibly the critical step.
7 month ago
How would I settle this?
4 month ago
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