In stimulate to solve this problem, you shouldMake an EquationThe equation is x+x+2+x+4+x+6+x+8+x+10= 204Simplify if possible.6x+30= 204Isolate the Variable6x+30-30=204-306x=174Make the Variable equal One6x÷6= 174÷6x=291st Number= 292nd Number= 29+23rd Number= 29+44th Number= 29+65th Number= 29+86th Number= 29+10You room trying to uncover the fourth numberso 29+6=35The prize is 35.Hope this helps.

You are watching: The sum of 6 consecutive odd numbers is 204



The 5th number is 44

Define x:

Let the the smallest number be x

The other 4 numbers room ( x + 2), ( x + 4), ( x + 6) and (x + 8)

Solve x :

The sum is 200

x + (x + 2) + (x + 4) + (x + 6) + (x + 8) = 200

x + x + 2 + x + 4 + x + 6 + x + 8 = 200

5x + 20 = 200

5x = 180

x = 36

Find the fifth number:

5th number = x + 8 = 36 + 8 = 44




29,31,33,35,37,39

Step-by-step explanation:

"X" will certainly be the median of the 6 numbers, this will certainly be an also number, the 6 odd number are:

x-5, x-3, x-1, x+1, x+3, x+5

NEXT:

204=(x-5) + (x-3) + (×-1) + ( x+1) + (×+3) + (x+5)=6x

divide both ends by 6 come find:

X=204÷6 =34

▪︎ This way the 6 odd numbers are:

29, 31, 33, 35, 37, 39




36, 38, 40, 42, 44

Step-by-step explanation:

You room implying that you are including up 5 continually numbers, and also should use the word "add" or the word "sum."

"The sum of 5 consecutive odd numbers is 200" leads to:

x + (x+2) + (x+4) + (x+6) + (x+8) = 200. Note how each number is 2 much more than the number coming before it. In this method you deserve to guarantee that every one of the 5 numbers room odd.

Summing up, we get 5x + 20 = 200, or 5x = 180.

Dividing both political parties by 5, we acquire x = 36.

Then the 5 continually integers room

36, 38, 40, 42, 44. These add up to 200.

Unfortunately, these room consecutive also numbers, not odd numbers.

Please ensure the you have copied down this trouble correctly.


Answer from: cxndii13
Hello , x + (x+2) = 2082x + 2 = 2082x = 208 - 2 2x = 206x = 206/2x = 103 the 2 numbers room : 103 and also 105 .
Answer from: Kay6718
Let number be2n+1 , 2n+3, 2n+5, 2n+7, 2n+9,2n+ 11 and also these add up to 20412n + 36 = 20412n = 168n = 14so 4th number in the succession is 2(28) + 7 = 63
Answer from: makylahoyle
Let the very first number it is in x 1st number = x2nd number = x + 23rd number = x + 44th number = x + 65th number = x + 8x + x + 2 + x + 4 + x + 6 + x + 8 = 1205x + 20 = 1205x = 100x = 203rd number = x + 4 = 20 + 4 = 24 24
Answer from: neonaandrews10
The 6 strange consecutive number are:29+31+33+35+37+39 = 204

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