But it transforms out that publications disproves the statement speak \$sqrt2cdotsqrt2=2\$ i m sorry is a reasonable number and hence Product of 2 irrational number need not constantly be irrational. I m sorry I discover convincing.

You are watching: The product of two irrational numbers is rational

Can someone please allude out wherein am ns going not correct in mine proof?

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edited january 11 "15 in ~ 17:35

boy name Sleziak
request Sep 25 "13 at 4:48

Amit TomarAmit Tomar
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\$egingroup\$ The contrapositive is \$ eg q implies eg p\$. \$endgroup\$
–user61527
Sep 25 "13 at 4:50

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The negation of the assertion <Is the product of 2 irrational numbers> is the assertion <Is no the product of 2 irrational numbers>. There is no a priori factor to expect that the delinquent <Is no the product of 2 irrational numbers> is indistinguishable to the assertion <Is the product of two rational numbers> (and in fact these critical two room not equivalent).

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edited Sep 25 "13 in ~ 8:03
answered Sep 25 "13 at 5:27

DidDid
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Disprove:

Let \$sqrt2\$ be the irrational number. Climate \$sqrt2 imes sqrt2=|2|\$, i beg your pardon is rational. So, the product of two irrational number is not always irrational

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answer Sep 28 "14 in ~ 6:57

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Some an ext examples room

\$\$sqrt8×sqrt2=sqrt16 =4\$\$

\$\$sqrt2×sqrt32=sqrt64 =8\$\$

\$\$sqrt5×sqrt5=sqrt25 =5\$\$

In this means product of 2 irrational number is rational.

See more: What Are The Factors Of 361 ? What Are All The Factors Of 361

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edited Jul 25 "15 in ~ 18:26

Peter Woolfitt
reply Jul 25 "15 in ~ 17:59
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