But it transforms out that publications disproves the statement speak $sqrt2cdotsqrt2=2$ i m sorry is a reasonable number and hence Product of 2 irrational number need not constantly be irrational. I m sorry I discover convincing.
You are watching: The product of two irrational numbers is rational
Can someone please allude out wherein am ns going not correct in mine proof?
discrete-aramuseum.orgematics logic propositional-calculus irrational-numbers
edited january 11 "15 in ~ 17:35
boy name Sleziak
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request Sep 25 "13 at 4:48
Amit TomarAmit Tomar
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$egingroup$ The contrapositive is $ eg q implies eg p$. $endgroup$
Sep 25 "13 at 4:50
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The negation of the assertion <Is the product of 2 irrational numbers> is the assertion <Is no the product of 2 irrational numbers>. There is no a priori factor to expect that the delinquent <Is no the product of 2 irrational numbers> is indistinguishable to the assertion <Is the product of two rational numbers> (and in fact these critical two room not equivalent).
edited Sep 25 "13 in ~ 8:03
answered Sep 25 "13 at 5:27
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Let $sqrt2$ be the irrational number. Climate $sqrt2 imes sqrt2=|2|$, i beg your pardon is rational. So, the product of two irrational number is not always irrational
answer Sep 28 "14 in ~ 6:57
Hassan MuhammadHassan Muhammad
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Some an ext examples room
In this means product of 2 irrational number is rational.
See more: What Are The Factors Of 361 ? What Are All The Factors Of 361
edited Jul 25 "15 in ~ 18:26
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reply Jul 25 "15 in ~ 17:59
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