But it transforms out that publications disproves the statement speak $sqrt2cdotsqrt2=2$ i m sorry is a reasonable number and hence Product of 2 irrational number need not constantly be irrational. I m sorry I discover convincing.

You are watching: The product of two irrational numbers is rational

Can someone please allude out wherein am ns going not correct in mine proof?


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edited january 11 "15 in ~ 17:35
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boy name Sleziak
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Amit TomarAmit Tomar
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$egingroup$ The contrapositive is $ eg q implies eg p$. $endgroup$
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The negation of the assertion <Is the product of 2 irrational numbers> is the assertion <Is no the product of 2 irrational numbers>. There is no a priori factor to expect that the delinquent <Is no the product of 2 irrational numbers> is indistinguishable to the assertion <Is the product of two rational numbers> (and in fact these critical two room not equivalent).


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DidDid
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Disprove:

Let $sqrt2$ be the irrational number. Climate $sqrt2 imes sqrt2=|2|$, i beg your pardon is rational. So, the product of two irrational number is not always irrational


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Hassan MuhammadHassan Muhammad
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Some an ext examples room

$$sqrt8×sqrt2=sqrt16 =4$$

$$sqrt2×sqrt32=sqrt64 =8$$

$$sqrt5×sqrt5=sqrt25 =5$$

In this means product of 2 irrational number is rational.

See more: What Are The Factors Of 361 ? What Are All The Factors Of 361


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Peter Woolfitt
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