First point to carry out is to draw the system defined above. Then, create an equation because that the pressures present.ΣF = Fg - Ff0 = mgsin∅ - umgcos∅0 = gsin∅ - ugcos∅u = tan∅∅(max) = tan^-1 (u)

You are watching: The coefficient of static friction between hard rubber and normal street pavement is about 0.90

aramuseum.org: Ok, first, if the massive of the carr is M, and also the angle of the hill is a (counting counterclockwise native the ground), the equations for the forces are:

Gravity force Fg = - Mg*sin(a)

Knowing that the normal pressure that the floor is act in the car is N = Mg*cos(a)

then the Friction force is: Ff = 0.9*Mg*cos(a)

if the automobile is parked, then the sum of the forces must be equal to zero, this is

0.9*Mg*cos(a) - Mg*sin(a) = 0

Mg( 0.9*cos(a) - sin(a)) = 0

so

0.9*cos(a) = sin(a)

0.9 = sin(a)/cos(a) = Tg(a)

a = aTg(0.9) = 41.9°

so the maximum angle is 41.9°, if is smaller sized or equal, climate your vehicle will be fine.

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