Since the question is a little ambiguous, I will assume that you\"re dealing with three distinctive sets the quantum numbers.

In enhancement to this, ns will likewise assume that you\"re relatively familiar with quantum numbers, so ns won\"t get in too lot details about what every represents.

\"*\"

#1^\"st\"# set # -> n=2#

The principal quantum number, #n#, speak you the power level on which an electron resides. In order to be able to determine how plenty of electrons deserve to share this value of #n#, you must determine exactly how many orbitals you have actually in this energy level.

The variety of orbitals you acquire per energy level can be uncovered using the equation

#color(blue)(\"no. That orbitals\" = n^2)#

Since every orbital can hold amaximum of two electrons, it follows that as numerous as

#color(blue)(\"no. Of electrons\" = 2n^2)#

In this case, the 2nd energy level stop a total of

#\"no. That orbitals\" = n^2 = 2^2 = 4#

orbitals. Therefore, a best of

#\"no. That electrons\" = 2 * 4 = 8#

electrons deserve to share the quantum number #n=2#.

#2^\"nd\"# set #-> n=4, l=3#

This time, girlfriend are offered both the energy level, #n=4#, and the subshell, #l=3#, on i beg your pardon the electrons reside.

Now, the subshell is provided by the angular momentum quantum number, #l#, which have the right to take values varying from #0# to #n-1#.

#l=0 -># the s-subshell#l=1 -># the p-subshell#l=2 -># the d-subshell#l=3 -># the f-subshell

Now, the number of orbitals you get per subshell is provided by the magnetic quantum number, #m_l#, which in this case can be

#m_l = -l, ..., -1, 0, 1, ..., +l#

#m_l = -3; -2; -1; 0; 1; 2; 3#

So, the f-subshell deserve to hold total of seven orbitals, which method that you have a preferably of

#\"no. The electrons\" = 2 * 7 = 14#

electrons that deserve to share these two quantum numbers, #n=4# and also #l=3#.

#3^\"rd\"# set #-> n=6, l=2, m_l = -1#

This time, girlfriend are offered the power level, #n=6#, the subshell, #l=2#, and the exact orbital, #m_l = 1#, in i m sorry the electrons reside.


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Since you recognize the precise orbital, it follows that just two electrons have the right to share these 3 quantum numbers, one having spin-up, #m_s = +1/2#, and also the other having spin-down, #m_s = -1/2#.