To discover the steep intercept kind of the line that passes v (6,-1) and also (3,-7), we require to first find the slope of the line. This equation is m=(y2-y1)/(x2-x1). We deserve to plug in ours data point out to obtain m=(-7-(-1))/(3-6) and solve for m. We get 2 as our m. The first part that our steep intercept form is solved. Y=2x+b.

You are watching: Find the equation of the line in slope-intercept form containing the points (6, -1) and (-3, 2).

Now we have to solve for b. To carry out this, we can plug in a data point to our equation and also solve because that b. Let"s use the (6,-1) data point. -1=2(6)+b. When we resolve for b, we get -13.

Our ultimate equation in slope intercept form is y=2x-13. We have the right to validate this by plugging in among the data point out to acquire the pair.

Let"s use the (3,-7) point. Y=2(3)-13=6-13=-7. That"s the data point!

The can be fried equation in slope intercept form is y=2x-13.

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