aspect the expression through grouping. First, the expression requirements to be rewritten as x^2+ax+bx+16. To find a and b, collection up a mechanism to be solved.

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Since ab is positive, a and b have actually the same sign. Since a+b is negative, a and also b space both negative. List all together integer bag that provide product 16.

This is a perfect square trinomial, due to the fact that the an initial and last terms are perfect squaresdisplaystyleleft(sqrtx^2=xquad extandquadsqrt16=4
ight) ...

x2-8x+10 Final an outcome : x2 - 8x + 10 action by step solution : action 1 :Trying to variable by splitting the center term 1.1 Factoring x2-8x+10 The very first term is, x2 its coefficient is 1 . ...

What is the remainder as soon as x^100 -8x^99+12x^98-3x^10+24x^9-36x^8+3x^2-29x + 41 is divided by: x^2-8x+12.

https://math.stackexchange.com/questions/313044/what-is-the-remainder-when-x100-8x9912x98-3x1024x9-36x83x

very first note the r(x)=ax+b for part a,binmathbb Z because that x=2 you get r(2)=-5 (not r(x)=-5) Rightarrow 2a+b=-5. Carry out the very same for x=6 to discover r(6).Then find a,b.

displaystylex^2-8x+15=left(x-5
ight)cdotleft(x-3
ight) Explanation: displaystylex^2-8x+15=left(x-5
ight)cdotleft(x-3
ight)

x2-8x+17 Final result : x2 - 8x + 17 action by step solution : action 1 :Trying to aspect by separating the center term 1.1 Factoring x2-8x+17 The an initial term is, x2 that is coefficient is 1 . ...

-3x2-8x+16 Final result : (4 - 3x) • (x + 4) action by step solution : step 1 :Equation at the finish of step 1 : ((0 - 3x2) - 8x) + 16 action 2 : step 3 :Pulling out prefer terms : 3.1 traction ...

Factor the expression by grouping. First, the expression requirements to be rewritten as x^2+ax+bx+16. To discover a and also b, collection up a system to be solved.

Since abdominal is positive, a and also b have the very same sign. Due to the fact that a+b is negative, a and b space both negative. List all together integer bag that provide product 16.

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This trinomial has actually the form of a trinomial square, probably multiplied by a typical factor. Trinomial squares deserve to be factored by recognize the square roots of the leading and also trailing terms.