factor the expression by grouping. First, the expression needs to it is in rewritten together 7x^2+ax+bx-20. To find a and also b, collection up a device to be solved.

You are watching: 7x^2-31x-20

Since abdominal muscle is negative, a and also b have actually the opposite signs. Because a+b is positive, the positive number has higher absolute worth than the negative. Perform all such integer pairs that provide product -140.

displaystyleleft(9x-5
ight)left(x+4
ight) Explanation:Given - displaystyle9x^2_31x-20 find the product that -20 and 9.It is -180Find two numbers, the ...

7x2-31x-20 Final an outcome : (x - 5) • (7x + 4) action by action solution : step 1 :Equation at the finish of action 1 : (7x2 - 31x) - 20 action 2 :Trying to factor by dividing the center term ...

7x2+3x-2=0 Two remedies were discovered : x =(-3-√65)/14=-0.790 x =(-3+√65)/14= 0.362 action by step solution : step 1 :Equation at the finish of action 1 : (7x2 + 3x) - 2 = 0 step 2 :Trying to ...

5x2+31x-28 Final an outcome : (5x - 4) • (x + 7) step by action solution : action 1 :Equation at the end of action 1 : (5x2 + 31x) - 28 action 2 :Trying to aspect by dividing the middle term ...

x2+31x-32=0 Two solutions were found : x = 1 x = -32 action by step solution : step 1 :Trying to variable by splitting the center term 1.1 Factoring x2+31x-32 The an initial term is, x2 its ...

7x2-31x-20=0 Two solutions were found : x = -4/7 = -0.571 x = 5 step by step solution : step 1 :Equation at the end of step 1 : (7x2 - 31x) - 20 = 0 action 2 :Trying to element by separating ...

More Items

Factor the expression through grouping. First, the expression demands to be rewritten together 7x^2+ax+bx-20. To uncover a and b, set up a device to be solved.

Since ab is negative, a and also b have the opposite signs. Because a+b is positive, the confident number has better absolute worth than the negative. Perform all such integer pairs that offer product -140.

Quadratic polynomial have the right to be factored utilizing the change ax^2+bx+c=aleft(x-x_1
ight)left(x-x_2
ight), where x_1 and also x_2 space the options of the quadratic equation ax^2+bx+c=0.

All equations of the kind ax^2+bx+c=0 deserve to be addressed using the quadratic formula: frac-b±sqrtb^2-4ac2a. The quadratic formula gives two solutions, one once ± is enhancement and one as soon as it is subtraction.

See more: I Have A New England Firearms Pardner Serial Numbers, New England Firearm Model R92

Factor the original expression using ax^2+bx+c=aleft(x-x_1
ight)left(x-x_2
ight). Substitute frac47 because that x_1 and -5 for x_2.