### (7x^2-2x+16)+(6x^2+8x-46)

This faces simplification or other simple results.

## Step by step Solution ## Step 1 :

Equation at the finish of step 1 : (((7•(x2))-2x)+16)+(((2•3x2)+8x)-46)

## action 2 :

Equation at the end of action 2 : ((7x2 - 2x) + 16) + (6x2 + 8x - 46)

## Step 3 :

Trying to factor by splitting the center term3.1Factoring 13x2+6x-30 The very first term is, 13x2 the coefficient is 13.The middle term is, +6x its coefficient is 6.The critical term, "the constant", is -30Step-1 : main point the coefficient of the very first term by the continuous 13•-30=-390Step-2 : discover two determinants of -390 whose sum equals the coefficient that the middle term, which is 6.

 -390 + 1 = -389 -195 + 2 = -193 -130 + 3 = -127 -78 + 5 = -73 -65 + 6 = -59 -39 + 10 = -29 -30 + 13 = -17 -26 + 15 = -11 -15 + 26 = 11 -13 + 30 = 17 -10 + 39 = 29 -6 + 65 = 59 -5 + 78 = 73 -3 + 130 = 127 -2 + 195 = 193 -1 + 390 = 389

Observation : No two such factors can be discovered !! Conclusion : Trinomial deserve to not be factored